13194139533312 has 86 divisors (see below), whose sum is σ = 35184372088828. Its totient is φ = 4398046511104.

The previous prime is 13194139533299. The next prime is 13194139533349. The reversal of 13194139533312 is 21333593149131.

It is a Jordan-Polya number, since it can be written as 4! ⋅ (2!)³⁹.

It is an ABA number since it can be written as A⋅B^A, here for A=3, B=16384.

It is a super-3 number, since 3×13194139533312³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (48).

Its product of digits (787320) is a multiple of the sum of its prime divisors (5).

It is a nialpdrome in base 2, base 4, base 8 and base 16.

It is a zygodrome in base 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (2) of ones.

In principle, a polygon with 13194139533312 sides can be constructed with ruler and compass.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4398046511103 + 4398046511104 + 4398046511105.

Almost surely, 2^{13194139533312} is an apocalyptic number.

13194139533312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13194139533312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17592186044414).

13194139533312 is an abundant number, since it is smaller than the sum of its proper divisors (21990232555516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13194139533312 is an frugal number, since it uses more digits than its factorization.

13194139533312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87 (or 5 counting only the distinct ones).

The product of its digits is 787320, while the sum is 48.

Multiplying 13194139533312 by its sum of digits (48), we get a square (633318697598976 = 25165824²).

13194139533312 divided by its sum of digits (48) gives a 38-th power (274877906944 = 2³⁸).

The spelling of 13194139533312 in words is "thirteen trillion, one hundred ninety-four billion, one hundred thirty-nine million, five hundred thirty-three thousand, three hundred twelve".