Base | Representation |
---|---|
bin | 1111101111011… |
… | …00011000001001 |
3 | 100012110100002211 |
4 | 13313230120021 |
5 | 232300241301 |
6 | 21034025121 |
7 | 3162215566 |
oct | 767543011 |
9 | 305410084 |
10 | 132040201 |
11 | 68595837 |
12 | 382781a1 |
13 | 214812c7 |
14 | 1377186d |
15 | b8d3051 |
hex | 7dec609 |
132040201 has 2 divisors, whose sum is σ = 132040202. Its totient is φ = 132040200.
The previous prime is 132040193. The next prime is 132040261. The reversal of 132040201 is 102040231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104530176 + 27510025 = 10224^2 + 5245^2 .
It is an emirp because it is prime and its reverse (102040231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132040201 - 23 = 132040193 is a prime.
It is a super-2 number, since 2×1320402012 = 34869229360240802, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132040261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66020100 + 66020101.
It is an arithmetic number, because the mean of its divisors is an integer number (66020101).
Almost surely, 2132040201 is an apocalyptic number.
It is an amenable number.
132040201 is a deficient number, since it is larger than the sum of its proper divisors (1).
132040201 is an equidigital number, since it uses as much as digits as its factorization.
132040201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 132040201 is about 11490.8746838524. The cubic root of 132040201 is about 509.2160209001.
Adding to 132040201 its reverse (102040231), we get a palindrome (234080432).
The spelling of 132040201 in words is "one hundred thirty-two million, forty thousand, two hundred one".
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