Base | Representation |
---|---|
bin | 111101100001001011… |
… | …1110001011011000011 |
3 | 110121222222022220100202 |
4 | 1323002113301123003 |
5 | 4131030131434111 |
6 | 140405052235415 |
7 | 12354544505603 |
oct | 1730227613303 |
9 | 417888286322 |
10 | 132110030531 |
11 | 51033739316 |
12 | 2172b46bb6b |
13 | c5c50950cb |
14 | 6573806c03 |
15 | 368320cb3b |
hex | 1ec25f16c3 |
132110030531 has 2 divisors, whose sum is σ = 132110030532. Its totient is φ = 132110030530.
The previous prime is 132110030527. The next prime is 132110030551. The reversal of 132110030531 is 135030011231.
It is an a-pointer prime, because the next prime (132110030551) can be obtained adding 132110030531 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132110030531 - 22 = 132110030527 is a prime.
It is a super-2 number, since 2×1321100305312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132110030501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055015265 + 66055015266.
It is an arithmetic number, because the mean of its divisors is an integer number (66055015266).
Almost surely, 2132110030531 is an apocalyptic number.
132110030531 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110030531 is an equidigital number, since it uses as much as digits as its factorization.
132110030531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 132110030531 its reverse (135030011231), we get a palindrome (267140041762).
The spelling of 132110030531 in words is "one hundred thirty-two billion, one hundred ten million, thirty thousand, five hundred thirty-one".
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