Base | Representation |
---|---|
bin | 1111101111111… |
… | …10001011001100 |
3 | 100012121001002210 |
4 | 13313332023030 |
5 | 232310104400 |
6 | 21035350420 |
7 | 3162641250 |
oct | 767761314 |
9 | 305531083 |
10 | 132113100 |
11 | 68635589 |
12 | 382b2410 |
13 | 214a8542 |
14 | 13790260 |
15 | b8e9950 |
hex | 7dfe2cc |
132113100 has 144 divisors (see below), whose sum is σ = 445471488. Its totient is φ = 29602560.
The previous prime is 132113083. The next prime is 132113117. The reversal of 132113100 is 1311231.
It is an interprime number because it is at equal distance from previous prime (132113083) and next prime (132113117).
It is a super-2 number, since 2×1321131002 = 34907742383220000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 110707 + ... + 111893.
It is an arithmetic number, because the mean of its divisors is an integer number (3093552).
Almost surely, 2132113100 is an apocalyptic number.
132113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222735744).
132113100 is an abundant number, since it is smaller than the sum of its proper divisors (313358388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132113100 is a wasteful number, since it uses less digits than its factorization.
132113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1264 (or 1257 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
The square root of 132113100 is about 11494.0462849251. The cubic root of 132113100 is about 509.3097158732.
Adding to 132113100 its reverse (1311231), we get a palindrome (133424331).
The spelling of 132113100 in words is "one hundred thirty-two million, one hundred thirteen thousand, one hundred".
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