Base | Representation |
---|---|
bin | 11110000010100000111100… |
… | …000010100101001001000101 |
3 | 122022202222211211211000100120 |
4 | 132002200330002211021011 |
5 | 114304024341020144331 |
6 | 1144552232021532153 |
7 | 36553636032426252 |
oct | 3602407402451105 |
9 | 568688754730316 |
10 | 132114201334341 |
11 | 39106355496866 |
12 | 1299874a874059 |
13 | 589441486b5b5 |
14 | 248a50bbd4429 |
15 | 10418d8413796 |
hex | 78283c0a5245 |
132114201334341 has 16 divisors (see below), whose sum is σ = 177423452740800. Its totient is φ = 87442137039488.
The previous prime is 132114201334327. The next prime is 132114201334399. The reversal of 132114201334341 is 143433102411231.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 132114201334341 - 217 = 132114201203269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132114201332341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 199038786 + ... + 199701443.
It is an arithmetic number, because the mean of its divisors is an integer number (11088965796300).
Almost surely, 2132114201334341 is an apocalyptic number.
It is an amenable number.
132114201334341 is a deficient number, since it is larger than the sum of its proper divisors (45309251406459).
132114201334341 is a wasteful number, since it uses less digits than its factorization.
132114201334341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398741028.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 132114201334341 its reverse (143433102411231), we get a palindrome (275547303745572).
The spelling of 132114201334341 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred one million, three hundred thirty-four thousand, three hundred forty-one".
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