Base | Representation |
---|---|
bin | 11000100111000111… |
… | …01000110101100110 |
3 | 1021002211121112000222 |
4 | 30103203220311212 |
5 | 204030012330202 |
6 | 10023040404342 |
7 | 645300512561 |
oct | 142343506546 |
9 | 37084545028 |
10 | 13213011302 |
11 | 5670444a57 |
12 | 26890166b2 |
13 | 13275633aa |
14 | 8d4b774d8 |
15 | 524ecb4a2 |
hex | 3138e8d66 |
13213011302 has 4 divisors (see below), whose sum is σ = 19819516956. Its totient is φ = 6606505650.
The previous prime is 13213011263. The next prime is 13213011341. The reversal of 13213011302 is 20311031231.
13213011302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20311031231 = 17 ⋅1194766543.
It is an interprime number because it is at equal distance from previous prime (13213011263) and next prime (13213011341).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303252824 + ... + 3303252827.
It is an arithmetic number, because the mean of its divisors is an integer number (4954879239).
Almost surely, 213213011302 is an apocalyptic number.
13213011302 is a deficient number, since it is larger than the sum of its proper divisors (6606505654).
13213011302 is an equidigital number, since it uses as much as digits as its factorization.
13213011302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6606505653.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13213011302 its reverse (20311031231), we get a palindrome (33524042533).
The spelling of 13213011302 in words is "thirteen billion, two hundred thirteen million, eleven thousand, three hundred two".
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