Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111111011000110001010111 |
3 | 122022220202010121210222011002 |
4 | 132003011132333120301113 |
5 | 114310200222223433323 |
6 | 1145022241530133515 |
7 | 36556525333142363 |
oct | 3603053677306127 |
9 | 568822117728132 |
10 | 132153442405463 |
11 | 39120a62006356 |
12 | 129a428058129b |
13 | 589802961b1cb |
14 | 248c3916882a3 |
15 | 1042933487828 |
hex | 78315efd8c57 |
132153442405463 has 4 divisors (see below), whose sum is σ = 134965217775840. Its totient is φ = 129341667035088.
The previous prime is 132153442405447. The next prime is 132153442405493. The reversal of 132153442405463 is 364504244351231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132153442405463 - 24 = 132153442405447 is a prime.
It is a super-2 number, since 2×1321534424054632 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (47), and also a Moran number because the ratio is a prime number: 2811775370329 = 132153442405463 / (1 + 3 + 2 + 1 + 5 + 3 + 4 + 4 + 2 + 4 + 0 + 5 + 4 + 6 + 3).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132153442405403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1405887685118 + ... + 1405887685211.
It is an arithmetic number, because the mean of its divisors is an integer number (33741304443960).
Almost surely, 2132153442405463 is an apocalyptic number.
132153442405463 is a deficient number, since it is larger than the sum of its proper divisors (2811775370377).
132153442405463 is an equidigital number, since it uses as much as digits as its factorization.
132153442405463 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2811775370376.
The product of its (nonzero) digits is 4147200, while the sum is 47.
Adding to 132153442405463 its reverse (364504244351231), we get a palindrome (496657686756694).
The spelling of 132153442405463 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, four hundred five thousand, four hundred sixty-three".
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