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13220301121 = 21391618031
BaseRepresentation
bin11000100111111110…
…11100100101000001
31021010100022212210021
430103333130211001
5204033344113441
610023500533441
7645416463646
oct142377344501
937110285707
1013220301121
1156745739a5
12268b551281
131328c164b1
148d5b13dcd
1552596b3d1
hex313fdc941

13220301121 has 4 divisors (see below), whose sum is σ = 13220940544. Its totient is φ = 13219661700.

The previous prime is 13220301103. The next prime is 13220301167. The reversal of 13220301121 is 12110302231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13220301121 - 25 = 13220301089 is a prime.

It is a super-3 number, since 3×132203011213 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13220301095 and 13220301104.

It is not an unprimeable number, because it can be changed into a prime (13220304121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287625 + ... + 330406.

It is an arithmetic number, because the mean of its divisors is an integer number (3305235136).

Almost surely, 213220301121 is an apocalyptic number.

It is an amenable number.

13220301121 is a deficient number, since it is larger than the sum of its proper divisors (639423).

13220301121 is an equidigital number, since it uses as much as digits as its factorization.

13220301121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 639422.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13220301121 its reverse (12110302231), we get a palindrome (25330603352).

The spelling of 13220301121 in words is "thirteen billion, two hundred twenty million, three hundred one thousand, one hundred twenty-one".

Divisors: 1 21391 618031 13220301121