132223010220133 has 4 divisors (see below), whose sum is σ = 151112011680160. Its totient is φ = 113334008760108.

The previous prime is 132223010220131. The next prime is 132223010220139. The reversal of 132223010220133 is 331022010322231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132223010220133 - 2¹ = 132223010220131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132223010220098 and 132223010220107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132223010220131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9444500730003 + ... + 9444500730016.

It is an arithmetic number, because the mean of its divisors is an integer number (37778002920040).

Almost surely, 2^{132223010220133} is an apocalyptic number.

It is an amenable number.

132223010220133 is a deficient number, since it is larger than the sum of its proper divisors (18889001460027).

132223010220133 is an equidigital number, since it uses as much as digits as its factorization.

132223010220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18889001460026.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 132223010220133 its reverse (331022010322231), we get a palindrome (463245020542364).

The spelling of 132223010220133 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, ten million, two hundred twenty thousand, one hundred thirty-three".