Search a number
-
+
132377114657 is a prime number
BaseRepresentation
bin111101101001001001…
…0100111100000100001
3110122200120220011220102
41323102102213200201
54132102020132112
6140451352552145
712364266623534
oct1732222474041
9418616804812
10132377114657
11511604805a7
12217a49b2655
13c638509958
14659b08ca1b
15369b8b8bc2
hex1ed24a7821

132377114657 has 2 divisors, whose sum is σ = 132377114658. Its totient is φ = 132377114656.

The previous prime is 132377114567. The next prime is 132377114671. The reversal of 132377114657 is 756411773231.

Adding to 132377114657 its reverse (756411773231), we get a palindrome (888788887888).

Together with previous prime (132377114567) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102328972321 + 30048142336 = 319889^2 + 173344^2 .

It is a cyclic number.

It is not a de Polignac number, because 132377114657 - 230 = 131303372833 is a prime.

It is not a weakly prime, because it can be changed into another prime (132377116657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66188557328 + 66188557329.

It is an arithmetic number, because the mean of its divisors is an integer number (66188557329).

Almost surely, 2132377114657 is an apocalyptic number.

It is an amenable number.

132377114657 is a deficient number, since it is larger than the sum of its proper divisors (1).

132377114657 is an equidigital number, since it uses as much as digits as its factorization.

132377114657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 740880, while the sum is 47.

The spelling of 132377114657 in words is "one hundred thirty-two billion, three hundred seventy-seven million, one hundred fourteen thousand, six hundred fifty-seven".