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133013003 is a prime number
BaseRepresentation
bin1111110110110…
…01111000001011
3100021021202112112
413323121320023
5233022404003
621110532535
73203410004
oct773317013
9307252475
10133013003
116909a702
123866714b
1321732026
14139461ab
15ba263d8
hex7ed9e0b

133013003 has 2 divisors, whose sum is σ = 133013004. Its totient is φ = 133013002.

The previous prime is 133012991. The next prime is 133013009. The reversal of 133013003 is 300310331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133013003 - 212 = 133008907 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133013009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66506501 + 66506502.

It is an arithmetic number, because the mean of its divisors is an integer number (66506502).

Almost surely, 2133013003 is an apocalyptic number.

133013003 is a deficient number, since it is larger than the sum of its proper divisors (1).

133013003 is an equidigital number, since it uses as much as digits as its factorization.

133013003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 14.

The square root of 133013003 is about 11533.1263324391. The cubic root of 133013003 is about 510.4635065971.

Adding to 133013003 its reverse (300310331), we get a palindrome (433323334).

The spelling of 133013003 in words is "one hundred thirty-three million, thirteen thousand, three".