133023012426142 has 4 divisors (see below), whose sum is σ = 199534518639216. Its totient is φ = 66511506213070.

The previous prime is 133023012426131. The next prime is 133023012426169. The reversal of 133023012426142 is 241624210320331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 133023012426098 and 133023012426107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33255753106534 + ... + 33255753106537.

It is an arithmetic number, because the mean of its divisors is an integer number (49883629659804).

Almost surely, 2^{133023012426142} is an apocalyptic number.

133023012426142 is a deficient number, since it is larger than the sum of its proper divisors (66511506213074).

133023012426142 is an equidigital number, since it uses as much as digits as its factorization.

133023012426142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66511506213073.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 133023012426142 its reverse (241624210320331), we get a palindrome (374647222746473).

The spelling of 133023012426142 in words is "one hundred thirty-three trillion, twenty-three billion, twelve million, four hundred twenty-six thousand, one hundred forty-two".