Base | Representation |
---|---|
bin | 1100000110110000011111… |
… | …0001110101010111010111 |
3 | 1202010110001002210110200012 |
4 | 3001230013301311113113 |
5 | 3221033324420420310 |
6 | 44150345343110435 |
7 | 2542430003404040 |
oct | 301540761652727 |
9 | 52113032713605 |
10 | 13310234154455 |
11 | 4271925201787 |
12 | 15ab7425a241b |
13 | 7571c3b59704 |
14 | 34030c43d8c7 |
15 | 18136a557c05 |
hex | c1b07c755d7 |
13310234154455 has 8 divisors (see below), whose sum is σ = 18254035411872. Its totient is φ = 9127017705888.
The previous prime is 13310234154431. The next prime is 13310234154491. The reversal of 13310234154455 is 55445143201331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13310234154455 - 26 = 13310234154391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190146202172 + ... + 190146202241.
It is an arithmetic number, because the mean of its divisors is an integer number (2281754426484).
Almost surely, 213310234154455 is an apocalyptic number.
13310234154455 is a deficient number, since it is larger than the sum of its proper divisors (4943801257417).
13310234154455 is an equidigital number, since it uses as much as digits as its factorization.
13310234154455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 380292404425.
The product of its (nonzero) digits is 432000, while the sum is 41.
Adding to 13310234154455 its reverse (55445143201331), we get a palindrome (68755377355786).
The spelling of 13310234154455 in words is "thirteen trillion, three hundred ten billion, two hundred thirty-four million, one hundred fifty-four thousand, four hundred fifty-five".
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