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133102511153 is a prime number
BaseRepresentation
bin111101111110110000…
…1110010010000110001
3110201120010212010211022
41323331201302100301
54140043220324103
6141051344425225
712421255451243
oct1737541622061
9421503763738
10133102511153
11514a2996737
1221967918215
13c72289b851
146629558093
1536e0406138
hex1efd872431

133102511153 has 2 divisors, whose sum is σ = 133102511154. Its totient is φ = 133102511152.

The previous prime is 133102511147. The next prime is 133102511159. The reversal of 133102511153 is 351115201331.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (133102511147) and next prime (133102511159).

It can be written as a sum of positive squares in only one way, i.e., 130442324224 + 2660186929 = 361168^2 + 51577^2 .

It is a cyclic number.

It is not a de Polignac number, because 133102511153 - 214 = 133102494769 is a prime.

It is not a weakly prime, because it can be changed into another prime (133102511159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551255576 + 66551255577.

It is an arithmetic number, because the mean of its divisors is an integer number (66551255577).

Almost surely, 2133102511153 is an apocalyptic number.

It is an amenable number.

133102511153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133102511153 is an equidigital number, since it uses as much as digits as its factorization.

133102511153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 26.

Adding to 133102511153 its reverse (351115201331), we get a palindrome (484217712484).

The spelling of 133102511153 in words is "one hundred thirty-three billion, one hundred two million, five hundred eleven thousand, one hundred fifty-three".