Base | Representation |
---|---|
bin | 111101111110110011… |
… | …1101011000010010101 |
3 | 110201120020202112210101 |
4 | 1323331213223002111 |
5 | 4140044114220141 |
6 | 141051441454101 |
7 | 12421304536462 |
oct | 1737547530225 |
9 | 421506675711 |
10 | 133104054421 |
11 | 514a3850168 |
12 | 21968341331 |
13 | c722cbc120 |
14 | 662983a669 |
15 | 36e060d531 |
hex | 1efd9eb095 |
133104054421 has 16 divisors (see below), whose sum is σ = 144176800768. Its totient is φ = 122152147200.
The previous prime is 133104054401. The next prime is 133104054427. The reversal of 133104054421 is 124450401331.
It is a cyclic number.
It is not a de Polignac number, because 133104054421 - 25 = 133104054389 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133104054421.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133104054427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1866736 + ... + 1936726.
It is an arithmetic number, because the mean of its divisors is an integer number (9011050048).
Almost surely, 2133104054421 is an apocalyptic number.
It is an amenable number.
133104054421 is a deficient number, since it is larger than the sum of its proper divisors (11072746347).
133104054421 is a wasteful number, since it uses less digits than its factorization.
133104054421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70852.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 133104054421 its reverse (124450401331), we get a palindrome (257554455752).
The spelling of 133104054421 in words is "one hundred thirty-three billion, one hundred four million, fifty-four thousand, four hundred twenty-one".
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