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133111121300 = 22525931771171
BaseRepresentation
bin111101111111000001…
…0101000010110010100
3110201120202001120201122
41323332002220112110
54140102421340200
6141052253143112
712421421601563
oct1737602502624
9421522046648
10133111121300
11514a7837663
122196a78aa98
13c7245c4901
14662a759bda
1536e1057385
hex1efe0a8594

133111121300 has 72 divisors (see below), whose sum is σ = 294677701920. Its totient is φ = 52176150400.

The previous prime is 133111121281. The next prime is 133111121317. The reversal of 133111121300 is 3121111331.

133111121300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1331111213002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1834715 + ... + 1905885.

It is an arithmetic number, because the mean of its divisors is an integer number (4092745860).

Almost surely, 2133111121300 is an apocalyptic number.

133111121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133111121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147338850960).

133111121300 is an abundant number, since it is smaller than the sum of its proper divisors (161566580620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133111121300 is a wasteful number, since it uses less digits than its factorization.

133111121300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71561 (or 71554 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 133111121300 its reverse (3121111331), we get a palindrome (136232232631).

The spelling of 133111121300 in words is "one hundred thirty-three billion, one hundred eleven million, one hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 59 100 118 236 295 317 590 634 1180 1268 1475 1585 2950 3170 5900 6340 7925 15850 18703 31700 37406 71171 74812 93515 142342 187030 284684 355855 374060 467575 711710 935150 1423420 1779275 1870300 3558550 4199089 7117100 8398178 16796356 20995445 22561207 41990890 45122414 83981780 90244828 104977225 112806035 209954450 225612070 419908900 451224140 564030175 1128060350 1331111213 2256120700 2662222426 5324444852 6655556065 13311112130 26622224260 33277780325 66555560650 133111121300