Base | Representation |
---|---|
bin | 11110010100010000010101… |
… | …111110000101010101011011 |
3 | 122111002112122020202101001111 |
4 | 132110100111332011111123 |
5 | 114434013131313131324 |
6 | 1151324253203401151 |
7 | 40041005203433116 |
oct | 3624202576052533 |
9 | 574075566671044 |
10 | 133333333333339 |
11 | 39536392745977 |
12 | 12b54a876831b7 |
13 | 5952382a5c369 |
14 | 24cd52121757d |
15 | 106348ca5e794 |
hex | 794415f8555b |
133333333333339 has 2 divisors, whose sum is σ = 133333333333340. Its totient is φ = 133333333333338.
The previous prime is 133333333333303. The next prime is 133333333333427. The reversal of 133333333333339 is 933333333333331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133333333333339 - 29 = 133333333332827 is a prime.
It is a super-4 number, since 4×1333333333333394 (a number of 58 digits) contains 4444 as substring.
It is a plaindrome in base 10.
It is a junction number, because it is equal to n+sod(n) for n = 133333333333292 and 133333333333301.
It is not a weakly prime, because it can be changed into another prime (133333333333139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666666666669 + 66666666666670.
It is an arithmetic number, because the mean of its divisors is an integer number (66666666666670).
Almost surely, 2133333333333339 is an apocalyptic number.
133333333333339 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333333333339 is an equidigital number, since it uses as much as digits as its factorization.
133333333333339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14348907, while the sum is 49.
The spelling of 133333333333339 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, three hundred thirty-three million, three hundred thirty-three thousand, three hundred thirty-nine".
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