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13334025401 = 22036052667
BaseRepresentation
bin11000110101100010…
…10001010010111001
31021102021022200011122
430122301101102321
5204302002303101
610043042235025
7651300226424
oct143261212271
937367280148
1013334025401
115722789704
122701655a75
131346653a78
14906c789bb
1553093251b
hex31ac514b9

13334025401 has 4 divisors (see below), whose sum is σ = 13340080272. Its totient is φ = 13327970532.

The previous prime is 13334025389. The next prime is 13334025407. The reversal of 13334025401 is 10452043331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10452043331 = 66115812471.

It is a cyclic number.

It is not a de Polignac number, because 13334025401 - 218 = 13333763257 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13334025407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3024131 + ... + 3028536.

It is an arithmetic number, because the mean of its divisors is an integer number (3335020068).

Almost surely, 213334025401 is an apocalyptic number.

It is an amenable number.

13334025401 is a deficient number, since it is larger than the sum of its proper divisors (6054871).

13334025401 is an equidigital number, since it uses as much as digits as its factorization.

13334025401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6054870.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 13334025401 its reverse (10452043331), we get a palindrome (23786068732).

The spelling of 13334025401 in words is "thirteen billion, three hundred thirty-four million, twenty-five thousand, four hundred one".

Divisors: 1 2203 6052667 13334025401