Base | Representation |
---|---|
bin | 10011011011001001001… |
… | …010111100000001001011 |
3 | 11201121101112211010112102 |
4 | 103123021022330001023 |
5 | 133332200111340301 |
6 | 2501112220504015 |
7 | 165302646602624 |
oct | 23331112740113 |
9 | 4647345733472 |
10 | 1334814949451 |
11 | 475101270a95 |
12 | 1968429ab00b |
13 | 98b45b99449 |
14 | 48869284a4b |
15 | 24ac5600b6b |
hex | 136c92bc04b |
1334814949451 has 2 divisors, whose sum is σ = 1334814949452. Its totient is φ = 1334814949450.
The previous prime is 1334814949253. The next prime is 1334814949453. The reversal of 1334814949451 is 1549494184331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1334814949451 - 210 = 1334814948427 is a prime.
Together with 1334814949453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1334814949453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667407474725 + 667407474726.
It is an arithmetic number, because the mean of its divisors is an integer number (667407474726).
Almost surely, 21334814949451 is an apocalyptic number.
1334814949451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334814949451 is an equidigital number, since it uses as much as digits as its factorization.
1334814949451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7464960, while the sum is 56.
The spelling of 1334814949451 in words is "one trillion, three hundred thirty-four billion, eight hundred fourteen million, nine hundred forty-nine thousand, four hundred fifty-one".
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