Base | Representation |
---|---|
bin | 10011011011001001001… |
… | …010111100000001101011 |
3 | 11201121101112211010120121 |
4 | 103123021022330001223 |
5 | 133332200111340413 |
6 | 2501112220504111 |
7 | 165302646603001 |
oct | 23331112740153 |
9 | 4647345733517 |
10 | 1334814949483 |
11 | 475101271014 |
12 | 1968429ab037 |
13 | 98b45b99472 |
14 | 48869284a71 |
15 | 24ac5600b8d |
hex | 136c92bc06b |
1334814949483 has 2 divisors, whose sum is σ = 1334814949484. Its totient is φ = 1334814949482.
The previous prime is 1334814949469. The next prime is 1334814949487. The reversal of 1334814949483 is 3849494184331.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3849494184331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1334814949483 - 25 = 1334814949451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1334814949487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667407474741 + 667407474742.
It is an arithmetic number, because the mean of its divisors is an integer number (667407474742).
Almost surely, 21334814949483 is an apocalyptic number.
1334814949483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334814949483 is an equidigital number, since it uses as much as digits as its factorization.
1334814949483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 35831808, while the sum is 61.
The spelling of 1334814949483 in words is "one trillion, three hundred thirty-four billion, eight hundred fourteen million, nine hundred forty-nine thousand, four hundred eighty-three".
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