Base | Representation |
---|---|
bin | 1100001001111101101001… |
… | …1001010110001011101000 |
3 | 1202022201012020200221020121 |
4 | 3002133122121112023220 |
5 | 3222434122134213100 |
6 | 44231534252333024 |
7 | 2546416526616556 |
oct | 302373231261350 |
9 | 52281166627217 |
10 | 13365307335400 |
11 | 4293216615759 |
12 | 15ba352474174 |
13 | 75c45c96b647 |
14 | 342c54840bd6 |
15 | 1829e04ac51a |
hex | c27da6562e8 |
13365307335400 has 48 divisors (see below), whose sum is σ = 31155473779200. Its totient is φ = 5332164358080.
The previous prime is 13365307335379. The next prime is 13365307335409. The reversal of 13365307335400 is 453370356331.
13365307335400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13365307335409) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87164310 + ... + 87317509.
It is an arithmetic number, because the mean of its divisors is an integer number (649072370400).
Almost surely, 213365307335400 is an apocalyptic number.
13365307335400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13365307335400 is an abundant number, since it is smaller than the sum of its proper divisors (17790166443800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13365307335400 is a wasteful number, since it uses less digits than its factorization.
13365307335400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174482218 (or 174482209 counting only the distinct ones).
The product of its (nonzero) digits is 1020600, while the sum is 43.
The spelling of 13365307335400 in words is "thirteen trillion, three hundred sixty-five billion, three hundred seven million, three hundred thirty-five thousand, four hundred".
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