Base | Representation |
---|---|
bin | 10011100000000100111… |
… | …111011111111111101101 |
3 | 11202010001211001222212212 |
4 | 103200010333133333231 |
5 | 133424023032120331 |
6 | 2503350100140205 |
7 | 165551156144555 |
oct | 23400477377755 |
9 | 4663054058785 |
10 | 1340113551341 |
11 | 477380188014 |
12 | 197881397665 |
13 | 994ab856636 |
14 | 48c0cc74165 |
15 | 24cd588bd2b |
hex | 13804fdffed |
1340113551341 has 2 divisors, whose sum is σ = 1340113551342. Its totient is φ = 1340113551340.
The previous prime is 1340113551299. The next prime is 1340113551353. The reversal of 1340113551341 is 1431553110431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1138000366441 + 202113184900 = 1066771^2 + 449570^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340113551341 - 218 = 1340113289197 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1340113551298 and 1340113551307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340113551541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670056775670 + 670056775671.
It is an arithmetic number, because the mean of its divisors is an integer number (670056775671).
Almost surely, 21340113551341 is an apocalyptic number.
It is an amenable number.
1340113551341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340113551341 is an equidigital number, since it uses as much as digits as its factorization.
1340113551341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 1340113551341 its reverse (1431553110431), we get a palindrome (2771666661772).
The spelling of 1340113551341 in words is "one trillion, three hundred forty billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred forty-one".
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