1340121301 has 2 divisors, whose sum is σ = 1340121302. Its totient is φ = 1340121300.

The previous prime is 1340121283. The next prime is 1340121317. The reversal of 1340121301 is 1031210431.

It is an a-pointer prime, because the next prime (1340121317) can be obtained adding 1340121301 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 919666276 + 420455025 = 30326^2 + 20505^2 .

It is an emirp because it is prime and its reverse (1031210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121301 - 2¹⁷ = 1339990229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340121401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060650 + 670060651.

It is an arithmetic number, because the mean of its divisors is an integer number (670060651).

Almost surely, 2^1340121301 is an apocalyptic number.

It is an amenable number.

1340121301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121301 is an equidigital number, since it uses as much as digits as its factorization.

1340121301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1340121301 is about 36607.6672433522. The cubic root of 1340121301 is about 1102.5070369064.

Adding to 1340121301 its reverse (1031210431), we get a palindrome (2371331732).

The spelling of 1340121301 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, three hundred one".