1340131253 has 4 divisors (see below), whose sum is σ = 1360133280. Its totient is φ = 1320129228.

The previous prime is 1340131241. The next prime is 1340131259. The reversal of 1340131253 is 3521310431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340131253 - 2⁶ = 1340131189 is a prime.

It is a super-3 number, since 3×1340131253³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340131259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10000913 + ... + 10001046.

It is an arithmetic number, because the mean of its divisors is an integer number (340033320).

Almost surely, 2^1340131253 is an apocalyptic number.

It is an amenable number.

1340131253 is a deficient number, since it is larger than the sum of its proper divisors (20002027).

1340131253 is an equidigital number, since it uses as much as digits as its factorization.

1340131253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20002026.

The product of its (nonzero) digits is 1080, while the sum is 23.

The square root of 1340131253 is about 36607.8031709088. The cubic root of 1340131253 is about 1102.5097660432.

Adding to 1340131253 its reverse (3521310431), we get a palindrome (4861441684).

The spelling of 1340131253 in words is "one billion, three hundred forty million, one hundred thirty-one thousand, two hundred fifty-three".