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13403331321 = 34467777107
BaseRepresentation
bin11000111101110011…
…01001101011111001
31021121002201210000120
430132321221223321
5204422223100241
610053555523453
7653101302462
oct143671515371
937532653016
1013403331321
115758916226
1227208b9589
131357b0b6a3
14912159d69
15536a72666
hex31ee69af9

13403331321 has 4 divisors (see below), whose sum is σ = 17871108432. Its totient is φ = 8935554212.

The previous prime is 13403331311. The next prime is 13403331341. The reversal of 13403331321 is 12313330431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12313330431 = 34104443477.

It is a cyclic number.

It is not a de Polignac number, because 13403331321 - 218 = 13403069177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13403331291 and 13403331300.

It is not an unprimeable number, because it can be changed into a prime (13403331311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233888551 + ... + 2233888556.

It is an arithmetic number, because the mean of its divisors is an integer number (4467777108).

Almost surely, 213403331321 is an apocalyptic number.

It is an amenable number.

13403331321 is a deficient number, since it is larger than the sum of its proper divisors (4467777111).

13403331321 is an equidigital number, since it uses as much as digits as its factorization.

13403331321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467777110.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 13403331321 its reverse (12313330431), we get a palindrome (25716661752).

The spelling of 13403331321 in words is "thirteen billion, four hundred three million, three hundred thirty-one thousand, three hundred twenty-one".

Divisors: 1 3 4467777107 13403331321