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1341141414113 = 9831364335111
BaseRepresentation
bin10011100001000010010…
…000011111000011100001
311202012201110011211112102
4103201002100133003201
5133433124200222423
62504040054540145
7165615506633204
oct23410220370341
94665643154472
101341141414113
11477858401586
12197b09667655
139961379aa67
1448ca959593b
1524d45c23c28
hex1384241f0e1

1341141414113 has 4 divisors (see below), whose sum is σ = 1342505750208. Its totient is φ = 1339777078020.

The previous prime is 1341141414083. The next prime is 1341141414167. The reversal of 1341141414113 is 3114141411431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341141414113 - 236 = 1272421937377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341141714113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 682166573 + ... + 682168538.

It is an arithmetic number, because the mean of its divisors is an integer number (335626437552).

Almost surely, 21341141414113 is an apocalyptic number.

It is an amenable number.

1341141414113 is a deficient number, since it is larger than the sum of its proper divisors (1364336095).

1341141414113 is an equidigital number, since it uses as much as digits as its factorization.

1341141414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1364336094.

The product of its digits is 2304, while the sum is 29.

Adding to 1341141414113 its reverse (3114141411431), we get a palindrome (4455282825544).

The spelling of 1341141414113 in words is "one trillion, three hundred forty-one billion, one hundred forty-one million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 983 1364335111 1341141414113