Base | Representation |
---|---|
bin | 1100001101010110000100… |
… | …0101000101101110110101 |
3 | 1202112021010221011111102221 |
4 | 3003111201011011232311 |
5 | 3224412111242233044 |
6 | 44314343040402341 |
7 | 2553544255232341 |
oct | 303254105055665 |
9 | 52467127144387 |
10 | 13423401524149 |
11 | 43059182385a1 |
12 | 16096660163b1 |
13 | 764a8a60bb66 |
14 | 3459a6156621 |
15 | 184290755484 |
hex | c3561145bb5 |
13423401524149 has 2 divisors, whose sum is σ = 13423401524150. Its totient is φ = 13423401524148.
The previous prime is 13423401524123. The next prime is 13423401524177. The reversal of 13423401524149 is 94142510432431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8305318791025 + 5118082733124 = 2881895^2 + 2262318^2 .
It is a cyclic number.
It is not a de Polignac number, because 13423401524149 - 225 = 13423367969717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13423401524249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711700762074 + 6711700762075.
It is an arithmetic number, because the mean of its divisors is an integer number (6711700762075).
Almost surely, 213423401524149 is an apocalyptic number.
It is an amenable number.
13423401524149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13423401524149 is an equidigital number, since it uses as much as digits as its factorization.
13423401524149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 13423401524149 in words is "thirteen trillion, four hundred twenty-three billion, four hundred one million, five hundred twenty-four thousand, one hundred forty-nine".
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