Base | Representation |
---|---|
bin | 10011100010111101101… |
… | …011100110110001010011 |
3 | 11202102001202120122121102 |
4 | 103202331223212301103 |
5 | 134001344300334141 |
6 | 2505021345215015 |
7 | 166021022435054 |
oct | 23427553466123 |
9 | 4672052518542 |
10 | 1343212121171 |
11 | 478720252428 |
12 | 1983a703146b |
13 | 998837a06cb |
14 | 490245b872b |
15 | 24e1790199b |
hex | 138bdae6c53 |
1343212121171 has 2 divisors, whose sum is σ = 1343212121172. Its totient is φ = 1343212121170.
The previous prime is 1343212121101. The next prime is 1343212121261. The reversal of 1343212121171 is 1711212123431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1343212121171 - 210 = 1343212120147 is a prime.
It is a super-2 number, since 2×13432121211712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1343212121101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671606060585 + 671606060586.
It is an arithmetic number, because the mean of its divisors is an integer number (671606060586).
Almost surely, 21343212121171 is an apocalyptic number.
1343212121171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343212121171 is an equidigital number, since it uses as much as digits as its factorization.
1343212121171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2016, while the sum is 29.
The spelling of 1343212121171 in words is "one trillion, three hundred forty-three billion, two hundred twelve million, one hundred twenty-one thousand, one hundred seventy-one".
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