Base | Representation |
---|---|
bin | 11110100010111100000001… |
… | …101010101100110100111001 |
3 | 122121122222222120101212000212 |
4 | 132202330001222230310321 |
5 | 120102031022331204312 |
6 | 1153420001043440505 |
7 | 40203624451664345 |
oct | 3642740152546471 |
9 | 577588876355025 |
10 | 134342310022457 |
11 | 398952877901a9 |
12 | 13098533986135 |
13 | 59c656ba05a64 |
14 | 25262b9928625 |
15 | 107e8423ea822 |
hex | 7a2f01aacd39 |
134342310022457 has 2 divisors, whose sum is σ = 134342310022458. Its totient is φ = 134342310022456.
The previous prime is 134342310022373. The next prime is 134342310022523. The reversal of 134342310022457 is 754220013243431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132029039371321 + 2313270651136 = 11490389^2 + 1520944^2 .
It is a cyclic number.
It is not a de Polignac number, because 134342310022457 - 230 = 134341236280633 is a prime.
It is not a weakly prime, because it can be changed into another prime (134342310024457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171155011228 + 67171155011229.
It is an arithmetic number, because the mean of its divisors is an integer number (67171155011229).
Almost surely, 2134342310022457 is an apocalyptic number.
It is an amenable number.
134342310022457 is a deficient number, since it is larger than the sum of its proper divisors (1).
134342310022457 is an equidigital number, since it uses as much as digits as its factorization.
134342310022457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 41.
Adding to 134342310022457 its reverse (754220013243431), we get a palindrome (888562323265888).
The spelling of 134342310022457 in words is "one hundred thirty-four trillion, three hundred forty-two billion, three hundred ten million, twenty-two thousand, four hundred fifty-seven".
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