13440100213 has 4 divisors (see below), whose sum is σ = 13726059840. Its totient is φ = 13154140588.

The previous prime is 13440100099. The next prime is 13440100273. The reversal of 13440100213 is 31200104431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31200104431 = 40163 ⋅776837.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440100213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440100273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142979743 + ... + 142979836.

It is an arithmetic number, because the mean of its divisors is an integer number (3431514960).

Almost surely, 2^13440100213 is an apocalyptic number.

It is an amenable number.

13440100213 is a deficient number, since it is larger than the sum of its proper divisors (285959627).

13440100213 is an equidigital number, since it uses as much as digits as its factorization.

13440100213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285959626.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13440100213 its reverse (31200104431), we get a palindrome (44640204644).

The spelling of 13440100213 in words is "thirteen billion, four hundred forty million, one hundred thousand, two hundred thirteen".