Base | Representation |
---|---|
bin | 11110100011110100111101… |
… | …011101001011010100011101 |
3 | 122121212211210000020020000220 |
4 | 132203310331131023110131 |
5 | 120104031222304334240 |
6 | 1153504031132111553 |
7 | 40211220413526321 |
oct | 3643647535132435 |
9 | 577784700206026 |
10 | 134403442652445 |
11 | 399091a85399aa |
12 | 130a83550055b9 |
13 | 59cc261cc99b5 |
14 | 25292389b1981 |
15 | 108121e2cc5d0 |
hex | 7a3d3d74b51d |
134403442652445 has 16 divisors (see below), whose sum is σ = 216738779965440. Its totient is φ = 71117412174144.
The previous prime is 134403442652431. The next prime is 134403442652467. The reversal of 134403442652445 is 544256244304431.
It is not a de Polignac number, because 134403442652445 - 28 = 134403442652189 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35276492230 + ... + 35276496039.
It is an arithmetic number, because the mean of its divisors is an integer number (13546173747840).
Almost surely, 2134403442652445 is an apocalyptic number.
134403442652445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
134403442652445 is a deficient number, since it is larger than the sum of its proper divisors (82335337312995).
134403442652445 is a wasteful number, since it uses less digits than its factorization.
134403442652445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70552988404.
The product of its (nonzero) digits is 22118400, while the sum is 51.
Adding to 134403442652445 its reverse (544256244304431), we get a palindrome (678659686956876).
The spelling of 134403442652445 in words is "one hundred thirty-four trillion, four hundred three billion, four hundred forty-two million, six hundred fifty-two thousand, four hundred forty-five".
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