Base | Representation |
---|---|
bin | 111110100101110010… |
… | …1000110000001111000 |
3 | 110211221101220010202002 |
4 | 1331023211012001320 |
5 | 4200233433021100 |
6 | 141425323400132 |
7 | 12465566106125 |
oct | 1751345060170 |
9 | 424841803662 |
10 | 134412001400 |
11 | 52005086086 |
12 | 22072383048 |
13 | c8a0c7a351 |
14 | 671142974c |
15 | 376a36d2d5 |
hex | 1f4b946078 |
134412001400 has 96 divisors (see below), whose sum is σ = 323449275600. Its totient is φ = 51884313600.
The previous prime is 134412001393. The next prime is 134412001433. The reversal of 134412001400 is 4100214431.
134412001400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1344120014002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14338715 + ... + 14348085.
Almost surely, 2134412001400 is an apocalyptic number.
134412001400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134412001400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161724637800).
134412001400 is an abundant number, since it is smaller than the sum of its proper divisors (189037274200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134412001400 is a wasteful number, since it uses less digits than its factorization.
134412001400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11889 (or 11880 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 134412001400 its reverse (4100214431), we get a palindrome (138512215831).
The spelling of 134412001400 in words is "one hundred thirty-four billion, four hundred twelve million, one thousand, four hundred".
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