Base | Representation |
---|---|
bin | 10011100100000101010… |
… | …010001010011110100111 |
3 | 11202112011111000111210011 |
4 | 103210011102022132213 |
5 | 134011324313124424 |
6 | 2505340501111051 |
7 | 166062550305343 |
oct | 23440522123647 |
9 | 4675144014704 |
10 | 1344413411239 |
11 | 47918735a438 |
12 | 1986813b8487 |
13 | 99a15627132 |
14 | 490d9d62623 |
15 | 24e880e4694 |
hex | 1390548a7a7 |
1344413411239 has 2 divisors, whose sum is σ = 1344413411240. Its totient is φ = 1344413411238.
The previous prime is 1344413411227. The next prime is 1344413411293. The reversal of 1344413411239 is 9321143144431.
Together with next prime (1344413411293) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344413411239 - 29 = 1344413410727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344413411339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672206705619 + 672206705620.
It is an arithmetic number, because the mean of its divisors is an integer number (672206705620).
Almost surely, 21344413411239 is an apocalyptic number.
1344413411239 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344413411239 is an equidigital number, since it uses as much as digits as its factorization.
1344413411239 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 124416, while the sum is 40.
The spelling of 1344413411239 in words is "one trillion, three hundred forty-four billion, four hundred thirteen million, four hundred eleven thousand, two hundred thirty-nine".
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