Base | Representation |
---|---|
bin | 11001000011110000… |
… | …11101110011010011 |
3 | 1021201120212002200202 |
4 | 30201320131303103 |
5 | 210023024232042 |
6 | 10102544005415 |
7 | 654246415004 |
oct | 144170356323 |
9 | 37646762622 |
10 | 13453352147 |
11 | 5784080654 |
12 | 273560086b |
13 | 13652a3401 |
14 | 918a5b1ab |
15 | 53b153632 |
hex | 321e1dcd3 |
13453352147 has 2 divisors, whose sum is σ = 13453352148. Its totient is φ = 13453352146.
The previous prime is 13453352123. The next prime is 13453352183. The reversal of 13453352147 is 74125335431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13453352147 - 210 = 13453351123 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13453352147.
It is not a weakly prime, because it can be changed into another prime (13453352117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726676073 + 6726676074.
It is an arithmetic number, because the mean of its divisors is an integer number (6726676074).
Almost surely, 213453352147 is an apocalyptic number.
13453352147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13453352147 is an equidigital number, since it uses as much as digits as its factorization.
13453352147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 151200, while the sum is 38.
Adding to 13453352147 its reverse (74125335431), we get a palindrome (87578687578).
The spelling of 13453352147 in words is "thirteen billion, four hundred fifty-three million, three hundred fifty-two thousand, one hundred forty-seven".
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