Base | Representation |
---|---|
bin | 10011100101000000011… |
… | …010011011010100000001 |
3 | 11202121201121200102221011 |
4 | 103211000122123110001 |
5 | 134020342242324324 |
6 | 2510023135400521 |
7 | 166126254330334 |
oct | 23450032332401 |
9 | 4677647612834 |
10 | 1345405433089 |
11 | 479646324103 |
12 | 1988b9683141 |
13 | 99b42cccb03 |
14 | 491919d461b |
15 | 24ee524bc94 |
hex | 1394069b501 |
1345405433089 has 2 divisors, whose sum is σ = 1345405433090. Its totient is φ = 1345405433088.
The previous prime is 1345405433083. The next prime is 1345405433167. The reversal of 1345405433089 is 9803345045431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 939381593089 + 406023840000 = 969217^2 + 637200^2 .
It is a cyclic number.
It is not a de Polignac number, because 1345405433089 - 219 = 1345404908801 is a prime.
It is not a weakly prime, because it can be changed into another prime (1345405433083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672702716544 + 672702716545.
It is an arithmetic number, because the mean of its divisors is an integer number (672702716545).
Almost surely, 21345405433089 is an apocalyptic number.
It is an amenable number.
1345405433089 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345405433089 is an equidigital number, since it uses as much as digits as its factorization.
1345405433089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 49.
The spelling of 1345405433089 in words is "one trillion, three hundred forty-five billion, four hundred five million, four hundred thirty-three thousand, eighty-nine".
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