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13466549539 is a prime number
BaseRepresentation
bin11001000101010101…
…10011110100100011
31021202111200121010001
430202222303310203
5210034414041124
610104134520431
7654466532242
oct144252636443
937674617101
1013466549539
115790574a93
122739b06117
131367c44411
1491a6d4959
1553c3adb44
hex322ab3d23

13466549539 has 2 divisors, whose sum is σ = 13466549540. Its totient is φ = 13466549538.

The previous prime is 13466549477. The next prime is 13466549543. The reversal of 13466549539 is 93594566431.

13466549539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13466549539 - 215 = 13466516771 is a prime.

It is a super-2 number, since 2×134665495392 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13466549539.

It is not a weakly prime, because it can be changed into another prime (13466559539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6733274769 + 6733274770.

It is an arithmetic number, because the mean of its divisors is an integer number (6733274770).

Almost surely, 213466549539 is an apocalyptic number.

13466549539 is a deficient number, since it is larger than the sum of its proper divisors (1).

13466549539 is an equidigital number, since it uses as much as digits as its factorization.

13466549539 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10497600, while the sum is 55.

The spelling of 13466549539 in words is "thirteen billion, four hundred sixty-six million, five hundred forty-nine thousand, five hundred thirty-nine".