134983 has 4 divisors (see below), whose sum is σ = 135720. Its totient is φ = 134248.

The previous prime is 134951. The next prime is 134989. The reversal of 134983 is 389431.

134983 is nontrivially palindromic in base 13.

134983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 389431 = 7 ⋅55633.

It is a cyclic number.

It is not a de Polignac number, because 134983 - 2⁵ = 134951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134989) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153 + ... + 541.

It is an arithmetic number, because the mean of its divisors is an integer number (33930).

2¹³⁴⁹⁸³ is an apocalyptic number.

134983 is a deficient number, since it is larger than the sum of its proper divisors (737).

134983 is an equidigital number, since it uses as much as digits as its factorization.

134983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 736.

The product of its digits is 2592, while the sum is 28.

The square root of 134983 is about 367.4003266193. The cubic root of 134983 is about 51.2971250069.

The spelling of 134983 in words is "one hundred thirty-four thousand, nine hundred eighty-three".