Base | Representation |
---|---|
bin | 10000000110110… |
… | …00001010101011 |
3 | 100102012221200021 |
4 | 20003120022223 |
5 | 234041300042 |
6 | 21223421311 |
7 | 3230233504 |
oct | 1003301253 |
9 | 312187607 |
10 | 135103147 |
11 | 6a297aa3 |
12 | 392b4837 |
13 | 21cb44ba |
14 | 13d2bbab |
15 | bcda867 |
hex | 80d82ab |
135103147 has 2 divisors, whose sum is σ = 135103148. Its totient is φ = 135103146.
The previous prime is 135103123. The next prime is 135103151. The reversal of 135103147 is 741301531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135103147 - 27 = 135103019 is a prime.
It is not a weakly prime, because it can be changed into another prime (135103187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67551573 + 67551574.
It is an arithmetic number, because the mean of its divisors is an integer number (67551574).
Almost surely, 2135103147 is an apocalyptic number.
135103147 is a deficient number, since it is larger than the sum of its proper divisors (1).
135103147 is an equidigital number, since it uses as much as digits as its factorization.
135103147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 135103147 is about 11623.3879312359. The cubic root of 135103147 is about 513.1234017713.
Adding to 135103147 its reverse (741301531), we get a palindrome (876404678).
The spelling of 135103147 in words is "one hundred thirty-five million, one hundred three thousand, one hundred forty-seven".
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