135134113 has 4 divisors (see below), whose sum is σ = 139793940. Its totient is φ = 130474288.

The previous prime is 135134107. The next prime is 135134117. The reversal of 135134113 is 311431531.

135134113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311431531 = 41 ⋅7595891.

It can be written as a sum of positive squares in 2 ways, for example, as 49238289 + 85895824 = 7017^2 + 9268^2 .

It is a cyclic number.

It is not a de Polignac number, because 135134113 - 2¹⁷ = 135003041 is a prime.

It is a super-2 number, since 2×135134113² = 36522456992593538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135134117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2329870 + ... + 2329927.

It is an arithmetic number, because the mean of its divisors is an integer number (34948485).

Almost surely, 2^135134113 is an apocalyptic number.

It is an amenable number.

135134113 is a deficient number, since it is larger than the sum of its proper divisors (4659827).

135134113 is an equidigital number, since it uses as much as digits as its factorization.

135134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4659826.

The product of its digits is 540, while the sum is 22.

The square root of 135134113 is about 11624.7199106043. The cubic root of 135134113 is about 513.1626018585.

Adding to 135134113 its reverse (311431531), we get a palindrome (446565644).

The spelling of 135134113 in words is "one hundred thirty-five million, one hundred thirty-four thousand, one hundred thirteen".