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13525401301 is a prime number
BaseRepresentation
bin11001001100010110…
…10011111011010101
31021220121102120112221
430212023103323111
5210200000320201
610114040142341
7656113004566
oct144613237325
937817376487
1013525401301
115810811205
1227557679b1
1313771ab849
1492445416d
155426364a1
hex3262d3ed5

13525401301 has 2 divisors, whose sum is σ = 13525401302. Its totient is φ = 13525401300.

The previous prime is 13525401299. The next prime is 13525401349. The reversal of 13525401301 is 10310452531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13409408401 + 115992900 = 115799^2 + 10770^2 .

It is an emirp because it is prime and its reverse (10310452531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13525401301 - 21 = 13525401299 is a prime.

Together with 13525401299, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13525401361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762700650 + 6762700651.

It is an arithmetic number, because the mean of its divisors is an integer number (6762700651).

Almost surely, 213525401301 is an apocalyptic number.

It is an amenable number.

13525401301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13525401301 is an equidigital number, since it uses as much as digits as its factorization.

13525401301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 13525401301 its reverse (10310452531), we get a palindrome (23835853832).

The spelling of 13525401301 in words is "thirteen billion, five hundred twenty-five million, four hundred one thousand, three hundred one".