Base | Representation |
---|---|
bin | 11001001100010110… |
… | …10011111101100011 |
3 | 1021220121102120202012 |
4 | 30212023103331203 |
5 | 210200000321233 |
6 | 10114040143135 |
7 | 656113005161 |
oct | 144613237543 |
9 | 37817376665 |
10 | 13525401443 |
11 | 5810811324 |
12 | 2755767aab |
13 | 13771ab928 |
14 | 924454231 |
15 | 542636548 |
hex | 3262d3f63 |
13525401443 has 2 divisors, whose sum is σ = 13525401444. Its totient is φ = 13525401442.
The previous prime is 13525401419. The next prime is 13525401451. The reversal of 13525401443 is 34410452531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13525401443 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13525401493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762700721 + 6762700722.
It is an arithmetic number, because the mean of its divisors is an integer number (6762700722).
Almost surely, 213525401443 is an apocalyptic number.
13525401443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525401443 is an equidigital number, since it uses as much as digits as its factorization.
13525401443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13525401443 its reverse (34410452531), we get a palindrome (47935853974).
The spelling of 13525401443 in words is "thirteen billion, five hundred twenty-five million, four hundred one thousand, four hundred forty-three".
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