Search a number
-
+
13531200000 = 293552819
BaseRepresentation
bin11001001101000010…
…11011101000000000
31021221000100011212120
430212201123220000
5210202441400000
610114404324240
7656213205453
oct144641335000
937830304776
1013531200000
11581401191a
1227576a3680
13137845c026
1492512349a
15542dce6a0
hex32685ba00

13531200000 has 240 divisors, whose sum is σ = 45073052640. Its totient is φ = 3607040000.

The previous prime is 13531199939. The next prime is 13531200019. The reversal of 13531200000 is 213531.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4798591 + ... + 4801409.

It is an arithmetic number, because the mean of its divisors is an integer number (187804386).

Almost surely, 213531200000 is an apocalyptic number.

13531200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13531200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22536526320).

13531200000 is an abundant number, since it is smaller than the sum of its proper divisors (31541852640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13531200000 is an frugal number, since it uses more digits than its factorization.

13531200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2865 (or 2829 counting only the distinct ones).

The product of its (nonzero) digits is 90, while the sum is 15.

Adding to 13531200000 its reverse (213531), we get a palindrome (13531413531).

It can be divided in two parts, 13531 and 200000, that added together give a triangular number (213531 = T653).

The spelling of 13531200000 in words is "thirteen billion, five hundred thirty-one million, two hundred thousand".