Base | Representation |
---|---|
bin | 111111000101000110… |
… | …0000100011001110111 |
3 | 110221122121102012121221 |
4 | 1332022030010121313 |
5 | 4204411333441001 |
6 | 142121445251211 |
7 | 12533612310361 |
oct | 1761214043167 |
9 | 427577365557 |
10 | 135462405751 |
11 | 524a3aa6452 |
12 | 22306103b07 |
13 | ca0a78499a |
14 | 67b0b37d31 |
15 | 37cc6a91a1 |
hex | 1f8a304677 |
135462405751 has 2 divisors, whose sum is σ = 135462405752. Its totient is φ = 135462405750.
The previous prime is 135462405739. The next prime is 135462405773. The reversal of 135462405751 is 157504264531.
It is a weak prime.
It is an emirp because it is prime and its reverse (157504264531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135462405751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135462405698 and 135462405707.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135462403751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67731202875 + 67731202876.
It is an arithmetic number, because the mean of its divisors is an integer number (67731202876).
Almost surely, 2135462405751 is an apocalyptic number.
135462405751 is a deficient number, since it is larger than the sum of its proper divisors (1).
135462405751 is an equidigital number, since it uses as much as digits as its factorization.
135462405751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504000, while the sum is 43.
The spelling of 135462405751 in words is "one hundred thirty-five billion, four hundred sixty-two million, four hundred five thousand, seven hundred fifty-one".
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