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136035216422011 = 1011346883330911
BaseRepresentation
bin11110111011100100101010…
…110000000111010001111011
3122211122211200010110102210101
4132323210222300013101323
5120312300110401001021
61201153414331100231
740440135322651144
oct3673445260072173
9584584603412711
10136035216422011
113a38823626a785
12133106528a1677
135aba0b19228ca
1425841d5112acb
1510ad8c50b1a91
hex7bb92ac0747b

136035216422011 has 4 divisors (see below), whose sum is σ = 137382099753024. Its totient is φ = 134688333091000.

The previous prime is 136035216421987. The next prime is 136035216422023. The reversal of 136035216422011 is 110224612530631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136035216422011 - 219 = 136035215897723 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136035216422051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673441665355 + ... + 673441665556.

It is an arithmetic number, because the mean of its divisors is an integer number (34345524938256).

Almost surely, 2136035216422011 is an apocalyptic number.

136035216422011 is a deficient number, since it is larger than the sum of its proper divisors (1346883331013).

136035216422011 is a wasteful number, since it uses less digits than its factorization.

136035216422011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1346883331012.

The product of its (nonzero) digits is 51840, while the sum is 37.

Adding to 136035216422011 its reverse (110224612530631), we get a palindrome (246259828952642).

The spelling of 136035216422011 in words is "one hundred thirty-six trillion, thirty-five billion, two hundred sixteen million, four hundred twenty-two thousand, eleven".

Divisors: 1 101 1346883330911 136035216422011