Search a number
-
+
1360404331000 = 2353112134718401
BaseRepresentation
bin10011110010111110011…
…010101011100111111000
311211001102220202101211121
4103302332122223213320
5134242102002043000
62520543334035024
7200200042006561
oct23627632534770
94731386671747
101360404331000
11484a42863100
1219b7a47a8a74
139b393551330
1449bb5a0d168
15255c1de4b1a
hex13cbe6ab9f8

1360404331000 has 384 divisors, whose sum is σ = 3848591335680. Its totient is φ = 446899200000.

The previous prime is 1360404330983. The next prime is 1360404331007. The reversal of 1360404331000 is 1334040631.

It is a happy number.

It is a super-2 number, since 2×13604043310002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1360404331007) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 73921800 + ... + 73940200.

It is an arithmetic number, because the mean of its divisors is an integer number (10022373270).

Almost surely, 21360404331000 is an apocalyptic number.

1360404331000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1360404331000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1924295667840).

1360404331000 is an abundant number, since it is smaller than the sum of its proper divisors (2488187004680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1360404331000 is a wasteful number, since it uses less digits than its factorization.

1360404331000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18504 (or 18479 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1360404331000 its reverse (1334040631), we get a palindrome (1361738371631).

The spelling of 1360404331000 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred thirty-one thousand".