Base | Representation |
---|---|
bin | 1100011001000101101000… |
… | …1000100001101011010000 |
3 | 1210020112220000121002011222 |
4 | 3012101122020201223100 |
5 | 3241213301000304230 |
6 | 44551150133224212 |
7 | 2604245610623225 |
oct | 306213210415320 |
9 | 53215800532158 |
10 | 13625148447440 |
11 | 4383436101052 |
12 | 164078a792068 |
13 | 77aacc82644a |
14 | 35166425594c |
15 | 18964c24b6e5 |
hex | c645a221ad0 |
13625148447440 has 80 divisors (see below), whose sum is σ = 32619257765136. Its totient is φ = 5289580953600.
The previous prime is 13625148447437. The next prime is 13625148447461. The reversal of 13625148447440 is 4474484152631.
It can be written as a sum of positive squares in 8 ways, for example, as 8106069517456 + 5519078929984 = 2847116^2 + 2349272^2 .
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10128641 + ... + 11394720.
Almost surely, 213625148447440 is an apocalyptic number.
13625148447440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13625148447440 is an abundant number, since it is smaller than the sum of its proper divisors (18994109317696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13625148447440 is a wasteful number, since it uses less digits than its factorization.
13625148447440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21523608 (or 21523602 counting only the distinct ones).
The product of its (nonzero) digits is 10321920, while the sum is 53.
The spelling of 13625148447440 in words is "thirteen trillion, six hundred twenty-five billion, one hundred forty-eight million, four hundred forty-seven thousand, four hundred forty".
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