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13745000131 = 31617268641
BaseRepresentation
bin11001100110100010…
…00000111011000011
31022110220122100111221
430303101000323003
5211122210001011
610151523015511
7664420400452
oct146321007303
938426570457
1013745000131
115913770045
1227b720a597
1313b0838795
14945698b99
15556a62971
hex333440ec3

13745000131 has 8 divisors (see below), whose sum is σ = 14420985728. Its totient is φ = 13083552000.

The previous prime is 13745000099. The next prime is 13745000149. The reversal of 13745000131 is 13100054731.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13745000131 - 25 = 13745000099 is a prime.

It is a super-2 number, since 2×137450001312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13745000096 and 13745000105.

It is not an unprimeable number, because it can be changed into a prime (13745007131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3632430 + ... + 3636211.

It is an arithmetic number, because the mean of its divisors is an integer number (1802623216).

Almost surely, 213745000131 is an apocalyptic number.

13745000131 is the 74149-th centered pentagonal number.

13745000131 is a deficient number, since it is larger than the sum of its proper divisors (675985597).

13745000131 is an equidigital number, since it uses as much as digits as its factorization.

13745000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7268733.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 13745000131 its reverse (13100054731), we get a palindrome (26845054862).

The spelling of 13745000131 in words is "thirteen billion, seven hundred forty-five million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 31 61 1891 7268641 225327871 443387101 13745000131