139932 has 54 divisors (see below), whose sum is σ = 399672. Its totient is φ = 41184.

The previous prime is 139921. The next prime is 139939. The reversal of 139932 is 239931.

It is a nude number because it is divisible by every one of its digits.

It is a plaindrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 139896 and 139905.

It is a congruent number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 139932.

It is not an unprimeable number, because it can be changed into a prime (139939) by changing a digit.

139932 is an untouchable number, because it is not equal to the sum of proper divisors of any number.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 6073 + ... + 6095.

139932 is a Friedman number, since it can be written as 92*39^(3-1), using all its digits and the basic arithmetic operations.

2¹³⁹⁹³² is an apocalyptic number.

139932 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 139932, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199836).

139932 is an abundant number, since it is smaller than the sum of its proper divisors (259740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

139932 is a wasteful number, since it uses less digits than its factorization.

139932 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59 (or 41 counting only the distinct ones).

The product of its digits is 1458, while the sum is 27.

The square root of 139932 is about 374.0748588184. The cubic root of 139932 is about 51.9165327618.

Subtracting 139932 from its reverse (239931), we obtain a palindrome (99999).

It can be divided in two parts, 1399 and 32, that added together give a triangular number (1431 = T₅₃).

The spelling of 139932 in words is "one hundred thirty-nine thousand, nine hundred thirty-two".