140012000000421 has 4 divisors (see below), whose sum is σ = 186682666667232. Its totient is φ = 93341333333612.

The previous prime is 140012000000417. The next prime is 140012000000429. The reversal of 140012000000421 is 124000000210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140012000000421 - 2² = 140012000000417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140012000000421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140012000000429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23335333333401 + ... + 23335333333406.

It is an arithmetic number, because the mean of its divisors is an integer number (46670666666808).

Almost surely, 2^{140012000000421} is an apocalyptic number.

It is an amenable number.

140012000000421 is a deficient number, since it is larger than the sum of its proper divisors (46670666666811).

140012000000421 is an equidigital number, since it uses as much as digits as its factorization.

140012000000421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46670666666810.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 140012000000421 its reverse (124000000210041), we get a palindrome (264012000210462).

The spelling of 140012000000421 in words is "one hundred forty trillion, twelve billion, four hundred twenty-one", and thus it is an aban number.