Base | Representation |
---|---|
bin | 10100011000111110110… |
… | …000011001001110001111 |
3 | 11221221202212222112212201 |
4 | 110120332300121032033 |
5 | 140424140311241421 |
6 | 2551412532342331 |
7 | 203143226200105 |
oct | 24307660311617 |
9 | 4857685875781 |
10 | 1401212212111 |
11 | 4a0283845188 |
12 | 1a76931749a7 |
13 | a2197ab5a4a |
14 | 4bb675d7c75 |
15 | 266ae7adb91 |
hex | 1463ec1938f |
1401212212111 has 2 divisors, whose sum is σ = 1401212212112. Its totient is φ = 1401212212110.
The previous prime is 1401212212091. The next prime is 1401212212157. The reversal of 1401212212111 is 1112122121041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1401212212111 - 29 = 1401212211599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1401212213111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700606106055 + 700606106056.
It is an arithmetic number, because the mean of its divisors is an integer number (700606106056).
Almost surely, 21401212212111 is an apocalyptic number.
1401212212111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401212212111 is an equidigital number, since it uses as much as digits as its factorization.
1401212212111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 1401212212111 its reverse (1112122121041), we get a palindrome (2513334333152).
The spelling of 1401212212111 in words is "one trillion, four hundred one billion, two hundred twelve million, two hundred twelve thousand, one hundred eleven".
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